CUET CUET Mathematics 2024 - For I=[arrayll1 & 0 \\ 0 & 1array], if X and Y are square matrices of order 2 such that X Y=X and Y X=Y, then (Y^2+2 Y) equals to : | PYQs + Solutions

CUET Mathematics 2024

Algebra

Matrices & Determinants

Medium

For $I=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]$ , if $X$ and $Y$ are square matrices of order $2$ such that $X Y=X$ and $Y X=Y$ , then $\left(\mathrm{Y}^{2}+2 \mathrm{Y}\right)$ equals to :

2 Y

I+3 X

I+3 Y

3 \mathrm{Y}

Correct Option: 4

Related questions:

CUET Mathematics 2024

A

I

A^{2}=A

A(I-2 A)^{3}+2 A^{3}

CUET Mathematics 2024

A_{n \times n}

|\operatorname{adj} \mathrm{A}|=|\mathrm{A}|^{\mathrm{n}-1}

|\mathrm{A}|=|\operatorname{adj} \mathrm{A}|^{\mathrm{n}-1}

\mathrm{A}(\operatorname{adj} \mathrm{A})=|\mathrm{A}|

\left|\mathrm{A}^{-1}\right|=\frac{1}{|\mathrm{~A}|}

CUET Mathematics 2024

A

B

A B-B A