CUET Mathematics 2024 - The corner points of the feasible region determined by x+y ≤ 8, 2 x+y ≥ 8, x ≥ 0, y ≥ 0 are A(0,8), B(4,0) and C(8,0). If the objective function Z=a x+ by has its maximum value on the line segment A B, then the relation between a and b is : | PYQs + Solutions | AfterBoards
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CUET Mathematics 2024 PYQs

CUET Mathematics 2024

Algebra
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Linear Programming

Medium

The corner points of the feasible region determined by x+y8,2x+y8,x0,y0x+y \leq 8, 2 x+y \geq 8, x \geq 0, y \geq 0 are A(0,8),B(4,0)A(0,8), B(4,0) and C(8,0)C(8,0). If the objective function Z=ax+Z=a x+ by has its maximum value on the line segment ABA B, then the relation between aa and bb is :

Correct Option: 2
Let's calculate the value of ZZ at each corner point:
At point A(0,8)A(0,8): ZA=a(0)+b(8)=8bZ_A = a(0) + b(8) = 8b
At point B(4,0)B(4,0): ZB=a(4)+b(0)=4aZ_B = a(4) + b(0) = 4a
At point C(8,0)C(8,0): ZC=a(8)+b(0)=8aZ_C = a(8) + b(0) = 8a

For a maximum to occur on segment ABAB (not just at endpoints), the function must increase from CC to BB and from BB to AA.
For ZZ to increase from CC to BB: ZB>ZCZ_B > Z_C which means 4a>8a4a > 8a, so a<0a < 0
For ZZ to increase from BB to AA: ZA>ZBZ_A > Z_B which means 8b>4a8b > 4a, so 2b>a2b > a

For the maximum to occur exactly on segment ABAB, the level curves of ZZ must be parallel to ABAB.
The slope of ABAB is:
0840=84=2\dfrac{0-8}{4-0} = \dfrac{-8}{4} = -2
The slope of the level curves Z=ax+byZ=ax+by is ab-\dfrac{a}{b}
For these to be parallel: ab=2-\dfrac{a}{b} = -2
Which simplifies to: a=2ba = 2b

The relation between aa and bb is a=2ba = 2b.
We can verify: If a=2ba = 2b, then ZA=8bZ_A = 8b and ZB=4a=4(2b)=8bZ_B = 4a = 4(2b) = 8b, confirming equal values at both points.

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