CUET Mathematics 2024 - A die is rolled thrice. What is the probability of getting a number greater than 4 in the first and the second throw of dice and a number less than 4 in the third throw ? | PYQs + Solutions

CUET Mathematics 2024

Algebra

Probability

Easy

A die is rolled thrice. What is the probability of getting a number greater than $4$ in the first and the second throw of dice and a number less than $4$ in the third throw ?

\frac{1}{3}

\frac{1}{6}

\frac{1}{9}

\frac{1}{18}

✅ Correct Option: 4

On a standard die with faces numbered

1

through

6

Numbers greater than

4

5, 6

(total

2

possibilities)

Numbers less than

4

1, 2, 3

(total

3

possibilities)

For each throw:

Probability of getting a number

> 4 = \dfrac{2}{6} = \dfrac{1}{3}

Probability of getting a number

< 4 = \dfrac{3}{6} = \dfrac{1}{2}

Since all throws are independent events, we multiply the individual probabilities:

Probability =

\dfrac{1}{3} \times \dfrac{1}{3} \times \dfrac{1}{2}

= \dfrac{1}{18}

Related questions:

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X

$X$	0	1	2	otherwise
$P(X)$	$k$	$2k$	$3k$	$0$

CUET Mathematics 2024

CUET Mathematics 2024

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