CUET Mathematics 2024 - Three defective bulbs are mixed with 8 good ones. If three bulbs are drawn one by one with replacement, the probabilities of getting exactly 1 defective, more than 2 defective, no defective and more than 1 defective respectively are: | PYQs + Solutions

CUET Mathematics 2024

Algebra

Hard

$\frac{27}{1331}, \frac{576}{1331}, \frac{243}{1331}$ and $\frac{512}{1331}$

$\frac{27}{1331}, \frac{243}{1331}, \frac{576}{1331}$ and $\frac{512}{1331}$

$\frac{576}{1331}, \frac{27}{1331}, \frac{512}{1331}$ and $\frac{243}{1331}$

$\frac{243}{1331}, \frac{576}{1331}, \frac{512}{1331}$ and $\frac{27}{1331}$

✅ Correct Option: 3

Related questions:

CUET Mathematics 2024

A die is rolled thrice. What is the probability of getting a number greater than $4$ in the first and the second throw of dice and a number less than $4$ in the third throw ?

CUET Mathematics 2024

Two dice are thrown simultaneously. If X denotes the number of fours, then the expectation of X will be :

CUET Mathematics 2024

If the random variable ( X ) has the following distribution:

$ X $	0	1	2	otherwise
$ P(X) $	$ k $	$ 2k $	$ 3k $	$ 0 $

Match List-I with List-II:

List-I	List-II
(A) $ k $	(I) $ \frac{5}{6} $
(B) $ P(X < 2) $	(II) $ \frac{4}{3} $
(C) $ E(X) $	(III) $ \frac{1}{2} $
(D) $ P(1 \leq X \leq 2) $	(IV) $ \frac{1}{6} $

List-I	List-II
(A) \( k \)	(I) \( \frac{5}{6} \)
(B) \( P(X < 2) \)	(II) \( \frac{4}{3} \)
(C) \( E(X) \)	(III) \( \frac{1}{2} \)
(D) \( P(1 \leq X \leq 2) \)	(IV) \( \frac{1}{6} \)

CUET Mathematics 2024 PYQs

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