9:{"metadata":[["$","title","0",{"children":"CUET Mathematics 2024 - The area of the region enclosed between the curves 4 x^2=y and y=4 is : | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined First, <=t's find the points of intersection: 4x^2 = 4 x^2 = 1 x = \\± 1 So the curves intersect at (-1,4) and (1,4).

Rearranging the parabola equation: 4x^2=y becomes y=4x^2

To find the area, we integrate the difference between the upper curve (y=4) and lower curve (y=4x^2) from x=-1 to x=1: Area = _-1^1 [4 - 4x^2] dx = _-1^1 4 dx - _-1^1 4x^2 dx = 4 _-1^1 dx - 4 _-1^1 x^2 dx = 4[x]_-1^1 - 4[x^33]_-1^1 = 4(1-(-1)) - 4(1^33-(-1)^33) = 4 2 - 4(13--13) = 8 - 4 23 = 8 - 83 = 24 - 83 = 163

Therefore, the area of the region enclosed between the curves is 163 square units."}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"CUETMAT,MAT,Calculus,Application of Integrals"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"CUET Mathematics 2024 - The area of the region enclosed between the curves 4 x^2=y and y=4 is : | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined First, <=t's find the points of intersection: 4x^2 = 4 x^2 = 1 x = \\± 1 So the curves intersect at (-1,4) and (1,4).

Rearranging the parabola equation: 4x^2=y becomes y=4x^2

Therefore, the area of the region enclosed between the curves is 163 square units."}],["$","meta","9",{"property":"og:url","content":"https://www.afterboards.in/cuet-past-year-questions/cuet-mat-2024-01/29"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | CUET Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"CUET Mathematics 2024 - The area of the region enclosed between the curves 4 x^2=y and y=4 is : | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined First, <=t's find the points of intersection: 4x^2 = 4 x^2 = 1 x = \\± 1 So the curves intersect at (-1,4) and (1,4).

Rearranging the parabola equation: 4x^2=y becomes y=4x^2

Therefore, the area of the region enclosed between the curves is 163 square units."}],["$","meta","17",{"name":"twitter:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],"$L18","$L19","$L1a","$L1b","$L1c","$L1d","$L1e","$L1f","$L20"],"error":null,"digest":"$undefined"}

CUET Mathematics 2024 PYQs

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