CUET Mathematics - The corner points of a bounded feasible region determined by the following system of linear inequalities x + 3y ≤ 60, x + y ≥ 10, x ≤ y, x ≥ 0, y ≥ 0 are (0,10), (5,5), (15, 15) and (0, 20). Let z = 2px + qy, p, q > 0. If maximum of z occurs at both (15, 15) and (0, 20), then the relation between p and q is | PYQs + Solutions

CUET Mathematics 2025 26 May Shift 2

Algebra

Hard

core

$3p = 2q + 1$

$3p = 4q$

$6p = q$

$2p = 3q$

✅ Correct Option: 3

Related questions:

3 June Shift 1

If the feasible region of an LPP is bounded and the corresponding objective function is $z = 5x - 9y$ , then the objective function attains:

only maximum value in the feasible region
only minimum value in the feasible region
both maximum and minimum values in the feasible region
neither maximum nor minimum value in the feasible region

19 May Shift 1

The corner points of the bounded feasible region determined by the system of linear inequalities are $(0, 0)$ , $(2, 4)$ , $(0, 5)$ and $(4, 0)$ . If the maximum value of $z = ax + by$ , where $a, b > 0$ occurs at both $(2, 4)$ and $(4, 0)$ , then

30 May Shift 1

The solution set of the linear constraints $x - 2y \geq 0, 2x - y \leq -4, x \geq 0$ and $y \geq 0$ is

CUET Mathematics 2025 26 May Shift 2 PYQs

Keyboard Shortcuts