CUET Mathematics: Applied MathematicsProbability Distribution. Free, no login required.

Q1:

2026: 30 May Shift 2

Probability Distribution

Medium

Applied

There are 10% defective pens. In a sample of randomly selected 10 pens, the probability that atmost one pen is defective, is

Answer options
Option 1
Correct Answer
Explanation for 2026: 30 May Shift 2 MAT question 1

Q2:

2026: 30 May Shift 2

Probability Distribution

Medium

Applied

Match List-I with List-II

List-IList-II
(A) Mean of a normal variate X is 12 and standard deviation is 4, then the Z-score of data point 20 is(I) 1
(B) If X is Poisson variate such that P(X=1) = 2P(X=2), then the mean of X is(II) 8
(C) In a binomial distribution, if mean is 5 and variance is 4, then the number of trials is(III) 2
(D) In a binomial distribution, if n = 20 and q = 0.6, then its mean is(IV) 25

Choose the correct answer from the options given below:

Answer options
Option 4
Correct Answer
Explanation for 2026: 30 May Shift 2 MAT question 2

Q3:

2026: 30 May Shift 2

Probability Distribution

Hard

Applied

In a printing press of a publication house, there is a small chance 11000\frac{1}{1000} for any typing error in 20 pages, then the number of pages containing no error in printing two volumes of an Encyclopedia containing total 10000 pages are:

[Given: e−0.02=0.9802e^{-0.02}=0.9802]

Answer options
Option 3
Correct Answer
Explanation for 2026: 30 May Shift 2 MAT question 3

Q4:

2026: 30 May Shift 1

Probability Distribution

Medium

Applied

A box containing 10 wall clocks has three defective pieces in it. If random sample of two clocks is taken from the box, then the probability distribution of defective clocks is:

Answer options
Option 1
Correct Answer
Explanation for 2026: 30 May Shift 1 MAT question 4

Q5:

2026: 30 May Shift 1

Probability Distribution

Medium

Applied

On a multiple choice examination with four possible answers (out of which only one is correct) for each of five questions, what is the probability that a candidate would get four or more correct answers just by guessing?

Answer options
Option 2
Correct Answer
Explanation for 2026: 30 May Shift 1 MAT question 5

Q6:

2026: 30 May Shift 1

Probability Distribution

Medium

Applied

The number of telephone calls made daily in a certain community between 8 P.M. and 9 P.M. has a mean of 352 and standard deviation of 31. What percentage of time will there be more than 400 telephone calls made in this community between 8 P.M. to 9 P.M.?

[Given that: P(0≤Z≤1.55)=0.4394P(0\leq Z\leq1.55)=0.4394, where ZZ is the standard normal variate]

Answer options
Option 3
Correct Answer
Explanation for 2026: 30 May Shift 1 MAT question 6

Q7:

2026: 30 May Shift 1

Probability Distribution

Hard

Applied

A box contains 8 red and 2 white balls. If three balls are drawn, one by one, at random without replacement, then the variance of the number of white balls drawn is:

Answer options
Option 1
Correct Answer
Explanation for 2026: 30 May Shift 1 MAT question 7

Q8:

2026: 29 May Shift 2

Probability Distribution

Medium

Applied

If 0.1% of the bolts manufactured by a machine are found to be defective. Find the probability that, in a sample of 2000 bolts chosen at random, exactly 3 will be defective using the Poisson distribution. [Given e−2=0.1353e^{-2} =0.1353]

Answer options
Option 3
Correct Answer
Explanation for 2026: 29 May Shift 2 MAT question 8

Q9:

2026: 29 May Shift 2

Probability Distribution

Hard

Applied

In a binomial distribution, the sum of its mean and variance is 1.8. If the event was conducted 5 times, then the probability of 3 successes is

Answer options
Option 1
Correct Answer
Explanation for 2026: 29 May Shift 2 MAT question 9

Q10:

2026: 29 May Shift 2

Probability Distribution

Medium

Applied

The probability distribution of a discrete random variable is given below :

X12345
P(X)1/5m2/52m3m

Which of the following are correct?

A. P(2)=115P(2)=\frac{1}{15}

B. P(4)=215P(4)=\frac{2}{15}

C. P(X<2)=15P(X<2)=\frac{1}{5}

D. P(X≥4)=15P(X\geq4)=\frac{1}{5}

Choose the correct answer from the options given below:

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Q11:

2026: 29 May Shift 1

Probability Distribution

Easy

Applied

The mean of the number of tails in three tosses of a coin is :

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Q12:

2026: 29 May Shift 1

Probability Distribution

Easy

Applied

A random variable X has the following probability distribution:

X01234
P(X)0.10.150.300.300.15

Which of the following are correct?

(A) P(X≤1)=0.25P(X \le 1)=0.25

(B) P(X>3)=0.15P(X>3)=0.15

(C) P(X=2)=0.30P(X=2)=0.30

(D) P(X≤2)=0.55P(X \le 2)=0.55

Choose the correct answer from the options given below:

Answer options

Q13:

2026: 29 May Shift 1

Probability Distribution

Medium

Applied

If X is a Poisson variate such that 3P(X=2)=2P(X=1)3P(X=2)=2P(X=1), then P(X=0)P(X=0) is equal to: (Given e−4/3=0.264e^{-4/3}=0.264)

Answer options

Q14:

2026: 29 May Shift 1

Probability Distribution

Easy

Applied

Let X denote the number of scores in a test. If X is normally distributed with mean 100 and standard deviation 15, then the probability that X does not exceed 130 is,

(Given P(0≤Z≤2)=0.4772P(0 \le Z \le 2)=0.4772, where ZZ be the standard normal variate)

Answer options

Q15:

2026: 26 May Shift 2

Probability Distribution

Easy

Applied

A traffic police officer records the number of motorcycle riders that use a particular lane on a highway. He records that an average of 2.5 motorcycle riders use the lane every hour. Given that the number of motorcycles that use the particular lane follows a Poisson distribution. The probability that less than 2 motorcycle riders will use the lane within an hour will be:- (Use e2.5=12.2e^{2.5} = 12.2)

Answer options

Q16:

2026: 26 May Shift 2

Probability Distribution

Easy

Applied

In a random experiment, a collection of trials is called Bernoulli trials then which of the following statements are TRUE?

A. The number of trials is infinite.

B. Each trial has exactly two outcomes defined as success and failure.

C. The trials are dependent by nature.

D. The probability of success remains the same in each trial.

Choose the correct answer from the options given below:

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Q17:

2026: 25 May Shift 1

Probability Distribution

Medium

Applied

If XX is a random variable such that XX can take values 0,1, 2 or 3. Then the expectation of XX for the following data is :

XX0123
P(X)P(X)kkk2k^21−5k21-5k^2k2k^2

(where k>0k>0)

Answer options

Q18:

2026: 25 May Shift 1

Probability Distribution

Hard

Applied

If a random variable X follows poisson's distribution such that P(X=2)=9P(X=4)+90P(X=6)P(X=2) = 9P(X=4) + 90P(X=6), then the mean of X is

Answer options

Q19:

2026: 25 May Shift 1

Probability Distribution

Medium

Applied

The mean and variance of a random variable XX having a binomial distribution are 1 and 2/3 respectively. Then,

Match the LIST-I with LIST-II

LIST-ILIST-II
A. P(X=0)P(X=0)I. 1/271/27
B. P(X=3)P(X=3)II. 2/92/9
C. P(X=2)P(X=2)III. 4/94/9
D. P(X=1)P(X=1)IV. 8/278/27

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Answer options

Q20:

2026: 25 May Shift 1

Probability Distribution

Hard

Applied

If X is a random variable which can take values 0,1,2,3 such that E(X2)=2E(X)E(X^2) = 2E(X).

If P(X=0)=P(X=1)=m & P(X=2)=2mP(X=0) = P(X=1) = m\ \&\ P(X=2) = 2m, then which of the following are TRUE?

A. P(X=1)=113P(X=1) = \dfrac{1}{13}

B. P(X=3)=113P(X=3) = \dfrac{1}{13}

C. E(X)=1813E(X) = \dfrac{18}{13}

D. P(X=2)=613P(X=2) = \dfrac{6}{13}

Choose the correct answer from the options given below:

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Q21:

2026: 22 May Shift 2

Probability Distribution

Medium

Applied

If the heights of 300 students are normally distributed with mean 68 inches and standard deviation 3 inches. If Z is the standard normal variate such that P(0≤Z≤1.33)=0.4082,P(Z≥1.33)=0.0918P(0\le Z\le 1.33)=0.4082, P(Z\ge 1.33)=0.0918 and P(0≤Z≤1)=0.3413P(0\le Z\le 1)=0.3413, then which of the following statements are correct?

(A) There are 27 students whose height is greater than 72 inches.

(B) The number of students having heights less than or equal to 64 inches is 27.

(C) 210 students have their heights between 65 and 71 inches.

(D) There are 35 students whose height is greater then 72 inches.

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Q22:

2026: 22 May Shift 2

Probability Distribution

Medium

Applied

The probability that a man aged 35 years will die before reaching the age of 40 years may be taken as 0.018. Out of a group of 100 men, now aged 35 years, what is the approximate probability that one man will die within next five years?

(Given: e−1.8=0.1653e^{-1.8}=0.1653)

Answer options

Q23:

2026: 21 May Shift 2

Probability Distribution

Easy

Applied

A random variable X follows Poisson distribution. The variance of X is 2. The value of P(X=3)P(X=3) is

Answer options

Q24:

2026: 21 May Shift 2

Probability Distribution

Medium

Applied

If a random variable X follows binomial distribution with mean 43\dfrac{4}{3} and variance 89\dfrac{8}{9}. Which of the following are correct?

A. Probability of success is 13\dfrac{1}{3}.

B. Probability of failure is 23\dfrac{2}{3}.

C. Number of trials is 4.

D. P(X≥1)=3581P(X \ge 1) = \dfrac{35}{81}

Choose the correct answer from the options given below:

Answer options

Q25:

2026: 21 May Shift 2

Probability Distribution

Easy

Applied

In a single throw of a die, if X denotes the number on its upper face, then the mean of X is,

Answer options

Q26:

2026: 21 May Shift 2

Probability Distribution

Easy

Applied

The random variable X has a probability distribution P(X)P(X) of the following form, where kk is some real number.

P(X=x)={k,if x=0k2,if x=1 or 20,otherwiseP(X=x) = \begin{cases}k, & \text{if } x=0\\\dfrac{k}{2}, & \text{if } x=1 \text{ or } 2\\0, & \text{otherwise}\end{cases}

On the basis of the above information, match List-I with List-II

LIST-ILIST-II
A. Value of kkI. 14\dfrac{1}{4}
B. P(X<2)P(X<2)II. 0
C. P(X>1)P(X>1)III. 12\dfrac{1}{2}
D. P(X>2)P(X>2)IV. 34\dfrac{3}{4}

Choose the correct answer from the options given below:

Answer options

Q27:

2026: 19 May Shift 2

Probability Distribution

Medium

Applied

A car hire firm has two cars, which is hire out day by day. The number of demands for cars on each day is distributed as a Poisson distribution with mean 1.5. Then which of the following is/are TRUE? (use e−1.5=0.2231e^{-1.5} = 0.2231)

A. The probability of days when no car is required is 0.2231

B. The probability of days when some demand is refused is 0.1913

C. The probability of days when no car is required is 0.1913

D. The probability of days when some demand is refused is 0.2231

Choose the correct answer from the options given below:

Answer options

Q28:

2026: 19 May Shift 2

Probability Distribution

Easy

Applied

If XX is a discrete random variable which assumes values x1,x2,x3,...,xnx_1, x_2, x_3, ..., x_n with the respective probabilities p1,p2,.....,pnp_1, p_2, ....., p_n, then

Match the LIST-I with LIST-II

LIST-ILIST-II
A.∑i=1npi=\displaystyle\sum_{i=1}^{n} p_i =I.E(X2)E(X^2)
B.∑i=1npixi=\displaystyle\sum_{i=1}^{n} p_i x_i =II.Var(X)Var(X)
C.∑i=1npixi2=\displaystyle\sum_{i=1}^{n} p_i x_i^2 =III.11
D.E(X2)−{E(X)}2=E(X^2) - \{E(X)\}^2 =IV.E(X)E(X)

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Answer options

Q29:

2026: 19 May Shift 2

Probability Distribution

Easy

Applied

The mean and variance of a Binomial distribution are 4 and 4/3 respectively. The number of trials is

Answer options

Q30:

2026: 18 May Shift 2

Probability Distribution

Hard

Applied

A pair of dice is thrown 5 times. If getting a total of 7 is considered a success, then

Match the LIST-I with LIST-II

LIST-ILIST-II
A. Probability of no successI. 26(16)526\left(\dfrac{1}{6}\right)^5
B. Probability of 5 successesII. 2(56)52\left(\dfrac{5}{6}\right)^5
C. Probability of at least 4 successesIII. (16)5\left(\dfrac{1}{6}\right)^5
D. Probability of at most one successIV. (56)5\left(\dfrac{5}{6}\right)^5

Choose the correct answer from the options given below:

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