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Let f:R→Rf: \mathbb{R} \rightarrow \mathbb{R} be defined as f(x)=[x]f(x) = [x], where [x] denotes the greatest integer less than or equal to x. Then which of the following statements are correct?

(A) f is one-one but not onto

(B) f is not onto

(C) f is not one-one

(D) f is one-one and onto

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 1

The function f(x)=[x]f(x) = [x] is the greatest integer function (or floor function), where [x][x] gives the largest integer that is less than or equal to xx.

Examples:

[2.7]=2[2.7] = 2

[5]=5[5] = 5

[−1.3]=−2[-1.3] = -2


Checking if ff is one-one:

A function is one-one if different inputs always give different outputs.

Take x1=1.2x_1 = 1.2:

f(1.2)=[1.2]=1f(1.2) = [1.2] = 1

Take x2=1.7x_2 = 1.7:

f(1.7)=[1.7]=1f(1.7) = [1.7] = 1

Here x1≠x2x_1 \neq x_2 but f(x1)=f(x2)f(x_1) = f(x_2).

Therefore, ff is not one-one.

Statement (C) is correct.


Checking if ff is onto:

A function f:R→Rf: \mathbb{R} \to \mathbb{R} is onto if every real number is an output.

The output of [x][x] is always an integer: ...,−2,−1,0,1,2,......, -2, -1, 0, 1, 2, ...

For example, there is no xx where [x]=1.5[x] = 1.5.

Therefore, ff is not onto.

Statement (B) is correct.


Since ff is not one-one, statement (A) is incorrect.

Since ff is neither one-one nor onto, statement (D) is incorrect.


The correct statements are (B) and (C).

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