Skip to main contentSkip to solution

With respect to the following shaded feasible region (ABCDEFA), the maximum value of the objective function z = 3x + 4y – 2 is at point(s):

Figure for CUET Mathematics 2025 26 May Shift 2 question 6 (Algebra)

Solution

✅ Correct Option: 4

For linear programming problems, the maximum or minimum value of the objective function occurs at one or more corner points of the feasible region.


From the graph, identify the coordinates of each vertex:

  • Point A: (x1,y1)(x_1, y_1)
  • Point B: (x2,y2)(x_2, y_2)
  • Point C: (x3,y3)(x_3, y_3)
  • Point D: (x4,y4)(x_4, y_4)
  • Point E: (x5,y5)(x_5, y_5)
  • Point F: (x6,y6)(x_6, y_6)

Calculate z=3x+4y−2z = 3x + 4y - 2 at each corner point:

At Point A:

z=3(x1)+4(y1)−2z = 3(x_1) + 4(y_1) - 2

At Point B:

z=3(x2)+4(y2)−2z = 3(x_2) + 4(y_2) - 2

At Point C:

z=3(x3)+4(y3)−2z = 3(x_3) + 4(y_3) - 2

At Point D:

z=3(x4)+4(y4)−2z = 3(x_4) + 4(y_4) - 2

At Point E:

z=3(x5)+4(y5)−2z = 3(x_5) + 4(y_5) - 2

At Point F:

z=3(x6)+4(y6)−2z = 3(x_6) + 4(y_6) - 2


Comparing all calculated values, Point E gives the highest value of zz.

Therefore, the maximum value of the objective function occurs at Point E only.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question