CUET Mathematics Applied Mathematics > Financial Mathematics PYQs

As a factory owner, you have decided to purchase a heavy machinery after 10 years. It's expected price will be Rs. 1,00,00,000. For this you set aside a certain amount at the end of every year. Which of the following financial tool fits best for this purpose ?

A person started giving aside Rs. 10,000 each year for his child college education in a sinking fund the amount he will receive after 6 years. if the rate of interest is 10% per annum is : (Use $(1.1)^6 = 1.771$)

At 8% converted quarterly the present value of perpetuity of Rs. 8000 payable at the end of each quarter ( in rupees) is :

An asset costing Rs. 1,50,000 has a final scrap value of Rs. 25,000. If annual depreciation charge is Rs. 25,000, then useful life of the asset is :

A sum of Rs 60,000 invested at r percent compounded quarterly will provide payment at rupees 600 each at the end of every three months , then the value of r is :

Which of the following is not true

Mr. Jain takes a personal loan of rupees 10,00,000 at 12% rate of interest per annum for three years. His EMI by flat rate method is :

A vehicle has a scrap value of Rs 7,50,000 after 6 years of its purchase . If the annual depreciation charge is Rs 55,000, then the original cost of the vehicle is :

If the cash equivalent of a perpetuity of Rs.1200 payable at end of each half year is Rs.96,000, the annual rate of interest compounded half yearly is :

Let us consider an annuity whose periodic payment is Rs. R payable at the end of each payment period for 'n' periods, interest paid r% per period or $i = \frac{r}{100}$, so the amount of obligation can be given as _______.

Mr. X takes a personal loan of Rs.10,00,000 at the rate of 12% per annum for 6 years. Calculate his EMI by using flat rate method

If the life expectancy of an asset is 10 years, scrap value Rs.5,000 and annual depreciation of Rs.3000 per annum, then original cost of the asset is:

Mr. X invested Rs.20,000 in year 2022 for 5 years. If Compound annual growth rate for that investment turned out to be 12%, the end value of the investment will be : {Use $(1.12)^5 = 1.76$}

The effective rate that is equivalent to a nominal rate of 16% compounded semi-annually is :

The purchase price P of a Rs. 50,000, 6% bond, dividends payable semi-annually, redeemable at par in 10 years, if the yield rate is to be 5% compounded semi-annually. Then P is equal : [Given $(1.025)^{-20} = 0.61027094$]

The effective rate equivalent to a nominal rate of 8% per annum compounded semi annually is :

Ravi takes a loan of Rs. 40,000 at an interest of 12% per annum for a period of 4 year, then EMI by using flat method is :

A vehicle costing Rs. 10,50,000 has a final scrap value of Rs. 5,25,000. If annual depreciation charge is Rs. 75,000, then useful life of the vehicle is :

An asset costing Rs. 50,000 has a useful life of 4 years. The estimated scrap value is Rs. 10,000. By using linear depreciation method, the book value at the end of the second year is :

A company intends to create a sinking fund to replace at the end of 20$^{th}$ year assets costing Rs. 2,50,000. Then the value of the amount to be retained out of profits every year if the interest rate is 5% is : [Given $(1.05)^{20} = 2.6532$]

The present value of a perpetuity of Rs. 2,500 payable at the end of each year, if money is worth 10% compounded annually, is :

The EMI (in Rs.) under the flat rate on a loan of Rs. 6,00,000 with 20% annual interest for 5 years is :

The present value of a perpetuity of Rs. 6,240 payable at the beginning of each year, if money is worth 10% effective, is :

The effective rate that is equivalent to a nominal rate of 12% compounded quarterly is :

A company has issued a bond having a face value of Rs. 10,000 paying annual dividends at 8.5%. The bond will be redeemed at par at the end of 10 years, then the purchase price of this bond if the investor wishes a yield rate of 8% is : [Given $(1.08)^{-10} = 0.46319349$]

Mr. Ram took a loan of Rs. 4,00,000 at 10% annual interest rate and paid Rs. 20,000 as monthly instalment under flat rate system. What is the term of the loan ?

The present value of a perpetual income of ₹ $x$ payable at the end of each 6 months is ₹ 1,80,000. If the money is worth 5% compounded semi-annually, then the value of $x$ is ₹ :

A person buys a flat for which he makes down payment of ₹ 7,50,000 and the balance is to be paid in 10 years by monthly instalments of ₹ 22,000 each. If the bank charges interest at the rate of 12% per annum, then the actual price of the flat using flat rate system is :

A car costing ₹ 8,00,000 has scrap value of ₹ 3,00,000. If the book value of car at the end of fourth year is ₹ 6,00,000, then the useful life of the car is :

If Mr. Ravi borrows a sum of ₹ 1,50,000 at an interest rate of 10% (flat) for a tenure of 3 years, then his EMI based on above data is (approximately) ₹ :

A person takes a car loan of Rs 9,00,000 at the rate of 12% per annum for 5 years from a bank. The EMI under flat rate system is:

An asset costing Rs 2,00,000 has a useful life of 10 years and scrap value of Rs 40,000. Its book value at the end of year 6 by Straight Line Method, is :

The present value of a perpetuity of Rs 1,200 payable at the beginning of each year, if the money is worth 5% effective, is: