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The point estimate of the population standard deviation as per the below mentioned data from a simple random sample 6,10,15,12,9,8 will be :-

Solution

✅ Correct Option: 3

Given data from a simple random sample: 6, 10, 15, 12, 9, 8

Number of values n=6n = 6

The point estimate of the population standard deviation is the sample standard deviation using the (n−1)(n-1) formula.


Mean =6+10+15+12+9+86= \dfrac{6 + 10 + 15 + 12 + 9 + 8}{6}

Mean =606= \dfrac{60}{6}

Mean =10= 10


Calculate each deviation from the mean and square it:

Data ValueDeviationSquared Deviation
66−10=−46 - 10 = -4(−4)2=16(-4)^2 = 16
1010−10=010 - 10 = 0(0)2=0(0)^2 = 0
1515−10=515 - 10 = 5(5)2=25(5)^2 = 25
1212−10=212 - 10 = 2(2)2=4(2)^2 = 4
99−10=−19 - 10 = -1(−1)2=1(-1)^2 = 1
88−10=−28 - 10 = -2(−2)2=4(-2)^2 = 4

Sum of squared deviations =16+0+25+4+1+4= 16 + 0 + 25 + 4 + 1 + 4

Sum of squared deviations =50= 50


For estimating the population standard deviation from a sample, use (n−1)(n-1) in the denominator.

Sample variance =506−1= \dfrac{50}{6-1}

Sample variance =505= \dfrac{50}{5}

Sample variance =10= 10


Sample standard deviation =10= \sqrt{10}

Sample standard deviation =3.162= 3.162

Therefore, the point estimate of the population standard deviation is 3.1623.162.

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