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Consider the LPP: Maximize z=x+yz = x + y subject to the constraints x+2y≤70x + 2y \leq 70, 2x+y≤952x + y \leq 95, x,y≥0x,y \geq 0. The optimal feasible solution is

Solution

✅ Correct Option: 4

The objective is to maximize z=x+yz = x + y subject to:

  • x+2y≤70x + 2y \leq 70
  • 2x+y≤952x + y \leq 95
  • x,y≥0x, y \geq 0

Testing each option against the constraints:


For (20,35)(20, 35):

x+2y=20+2(35)=20+70=90x + 2y = 20 + 2(35) = 20 + 70 = 90

Since 90>7090 > 70, the first constraint is violated.


For (35,20)(35, 20):

x+2y=35+2(20)=35+40=75x + 2y = 35 + 2(20) = 35 + 40 = 75

Since 75>7075 > 70, the first constraint is violated.


For (30,25)(30, 25):

x+2y=30+2(25)=30+50=80x + 2y = 30 + 2(25) = 30 + 50 = 80

Since 80>7080 > 70, the first constraint is violated.


For (40,15)(40, 15):

x+2y=40+2(15)=40+30=70≤70x + 2y = 40 + 2(15) = 40 + 30 = 70 \leq 70

2x+y=2(40)+15=80+15=95≤952x + y = 2(40) + 15 = 80 + 15 = 95 \leq 95

x=40≥0x = 40 \geq 0 and y=15≥0y = 15 \geq 0

All constraints are satisfied.

z=x+y=40+15=55z = x + y = 40 + 15 = 55


The optimal feasible solution is (40,15)(40, 15) with maximum value z=55z = 55.

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