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Match List-I with List-II

List-IList-II
Differential EquationsOrder and degree
(A) ydx+xlog⁡(y/x)dy−2xdy=0ydx + x\log(y/x)dy - 2xdy = 0(I) Order : 2, degree:1
(B) (d3ydx3)2+3d2ydx2+2(dydx)4=y2\left(\frac{d^3y}{dx^3}\right)^2 + 3\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^4 = y^2(II) Order :1, degree:1
(C) dydx+log⁡(dydx)+x=y\frac{dy}{dx} + \log\left(\frac{dy}{dx}\right) + x = y(III) Order : 3, degree:2
(D) (dsdt)4+2sd2sdt2=0\left(\frac{ds}{dt}\right)^4 + 2s\frac{d^2s}{dt^2} = 0(IV) Order : 1, degree: Not defined

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

Order of a differential equation is the highest derivative present.

Degree of a differential equation is the power of the highest derivative, provided the equation is polynomial in derivatives.

If the derivative appears inside transcendental functions (logarithm, exponential, trigonometric), the degree is not defined.


For equation (A): ydx+xlog⁡(y/x)dy−2xdy=0ydx + x\log(y/x)dy - 2xdy = 0

Converting to standard form by dividing by dxdx:

y+xlog⁡(y/x)dydx−2xdydx=0y + x\log(y/x)\frac{dy}{dx} - 2x\frac{dy}{dx} = 0

The highest derivative is dydx\frac{dy}{dx}, so Order =1= 1

Power of dydx\frac{dy}{dx} is 11, so Degree =1= 1

(A) matches with (II)


For equation (B): (d3ydx3)2+3d2ydx2+2(dydx)4=y2\left(\frac{d^3y}{dx^3}\right)^2 + 3\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^4 = y^2

The derivatives present are dydx\frac{dy}{dx}, d2ydx2\frac{d^2y}{dx^2}, and d3ydx3\frac{d^3y}{dx^3}

The highest derivative is d3ydx3\frac{d^3y}{dx^3}, so Order =3= 3

Power of d3ydx3\frac{d^3y}{dx^3} is 22, so Degree =2= 2

(B) matches with (III)


For equation (C): dydx+log⁡(dydx)+x=y\frac{dy}{dx} + \log\left(\frac{dy}{dx}\right) + x = y

The highest derivative is dydx\frac{dy}{dx}, so Order =1= 1

The derivative appears inside a logarithm log⁡(dydx)\log\left(\frac{dy}{dx}\right)

The equation is not polynomial in the derivative, so Degree is not defined

(C) matches with (IV)


For equation (D): (dsdt)4+2sd2sdt2=0\left(\frac{ds}{dt}\right)^4 + 2s\frac{d^2s}{dt^2} = 0

The derivatives present are dsdt\frac{ds}{dt} and d2sdt2\frac{d^2s}{dt^2}

The highest derivative is d2sdt2\frac{d^2s}{dt^2}, so Order =2= 2

Power of d2sdt2\frac{d^2s}{dt^2} is 11, so Degree =1= 1

(D) matches with (I)


Final matching:

(A) - (II) Order: 1, degree: 1

(B) - (III) Order: 3, degree: 2

(C) - (IV) Order: 1, degree: Not defined

(D) - (I) Order: 2, degree: 1

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