CUET Mathematics - A line passes through the point with position vector 2i - j + 4k and is in the direction of the vector i + j - 2k. The equation of the line in Cartesian form is: | PYQs + Solutions

CUET Mathematics 2025 26 May Shift 2

Geometry

Medium

core

$\frac{x-2}{1} = \frac{y+1}{1} = \frac{4-z}{2}$

$\frac{x+2}{1} = \frac{y-1}{1} = \frac{z-4}{2}$

$\frac{x-2}{1} = \frac{y-1}{1} = \frac{z-4}{2}$

$\frac{x-2}{1} = \frac{y+1}{1} = \frac{z-4}{2}$

✅ Correct Option: 1

Related questions:

27 May Shift 1

Match List-I with List-II

List-I	List-II
(A) Line : $x = 2y + 1 = z - 1$	(I) Crosses $xz$ plane at (1, 0, 1)
(B) Line : $x + 1 = 2y + 1 = z$	(II) Crosses $xz$ plane at (0, 0, 1)
(C) Line : $x - 1 = 2y = z + 1$	(III) Crosses $xz$ plane at (1, 0, -1)
(D) Line : $x - 1 = 2y = z - 1$	(IV) Crosses $xz$ plane at (1, 0, 2)

Choose the correct answer from the options given below:

3 June Shift 1

If the lines $\frac{x - 5}{5\lambda + 2} = \frac{2 - y}{5} = \frac{1 - z}{-1}$ and $\frac{y+\frac{1}{2}}{2\lambda} = \frac{z - 1}{3}$ are perpendicular, then the value of $\lambda$ is equal to

19 May Shift 1

If the line $\frac{-x+1}{3} = \frac{-y-2}{-2k} = \frac{z+3}{2}$ and $\frac{-1+x}{3k} = \frac{-1 +y}{1} = \frac{-z+6}{5}$ are perpendicular, then the value of k is:

CUET Mathematics 2025 26 May Shift 2 PYQs

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