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Consider the following test:

H₀: μ ≤ 12

H₁: μ > 12

A sample of 36 provided a sample mean xˉ=16\bar{x} = 16 and a sample standard deviation S=4.2. Then the value of the t- test statistic is:

Solution

✅ Correct Option: 4

Given information:

Sample size n=36n = 36

Sample mean xˉ=16\bar{x} = 16

Sample standard deviation s=4.2s = 4.2

Hypothesized mean μ0=12\mu_0 = 12 (from H0:μ≤12H_0: \mu \leq 12)


The t-test statistic formula is:

t=xˉ−μ0s/nt = \dfrac{\bar{x} - \mu_0}{s/\sqrt{n}}


Calculate the standard error s/ns/\sqrt{n}:

n=36\sqrt{n} = \sqrt{36}

n=6\sqrt{n} = 6

sn=4.26\dfrac{s}{\sqrt{n}} = \dfrac{4.2}{6}

sn=0.7\dfrac{s}{\sqrt{n}} = 0.7


Calculate the t-statistic:

t=16−120.7t = \dfrac{16 - 12}{0.7}

t=40.7t = \dfrac{4}{0.7}

t=5.71t = 5.71


Therefore, the value of the t-test statistic is 5.715.71.

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