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In a Binomial distribution, the probability of getting a success is 34\frac{3}{4} and the variance is 38\frac{3}{8} then the probability of no success is:

Solution

✅ Correct Option: 3

In a Binomial distribution, the probability of success is p=34p = \frac{3}{4} and variance is 38\frac{3}{8}.

The probability of failure:

q=1−pq = 1 - p

q=1−34q = 1 - \frac{3}{4}

q=14q = \frac{1}{4}


For a binomial distribution, variance is given by:

Variance =npq= npq

38=n×34×14\frac{3}{8} = n \times \frac{3}{4} \times \frac{1}{4}

38=n×316\frac{3}{8} = n \times \frac{3}{16}

n=38×163n = \frac{3}{8} \times \frac{16}{3}

n=2n = 2


The probability of no success means X=0X = 0 (zero successes in n=2n = 2 trials).

P(X=0)=qnP(X = 0) = q^n

P(X=0)=(14)2P(X = 0) = \left(\frac{1}{4}\right)^2

P(X=0)=116P(X = 0) = \frac{1}{16}

Therefore, the probability of no success is 116\frac{1}{16}.

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