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If it is given that at x=1x = 1, the function f(x)=x4−62x2+2ax+bf(x) = x^4 - 62x^2 + 2ax + b attains its maximum value on the interval [0, 2], then the value of a is:

Solution

✅ Correct Option: 2

Given function: f(x)=x4−62x2+2ax+bf(x) = x^4 - 62x^2 + 2ax + b

The function attains its maximum value at x=1x = 1 on the interval [0,2][0, 2].

At a maximum point, the first derivative equals zero.


Taking the derivative of f(x)=x4−62x2+2ax+bf(x) = x^4 - 62x^2 + 2ax + b:

f′(x)=4x3−124x+2af'(x) = 4x^3 - 124x + 2a


Since the maximum occurs at x=1x = 1:

f′(1)=0f'(1) = 0

Substituting x=1x = 1:

4(1)3−124(1)+2a=04(1)^3 - 124(1) + 2a = 0

4−124+2a=04 - 124 + 2a = 0

−120+2a=0-120 + 2a = 0

2a=1202a = 120

a=60a = 60


Therefore, a=60a = 60

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