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In the linear programming problem maximize Z=4x+3yZ = 4x+3y subject to the constraints x+y≥8x+y \ge 8, 3x+5y≤153x+5y \le 15, x≥0,y≥0x\ge0, y\ge0, the feasible region has

Solution

✅ Correct Option: 4

From 3x+5y≤153x+5y\le15 with x,y≥0x,y\ge0 we get x≤5x\le5 and y≤3y\le3, so x+yx+y can never exceed 5. This contradicts x+y≥8x+y\ge8, so no point satisfies all constraints and the feasible region is empty.

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