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For the matrix A=[2−1−10231−21]A = \begin{bmatrix} 2 & -1 & -1 \\ 0 & 2 & 3 \\ 1 & -2 & 1 \end{bmatrix}, which of the following statements are correct?

(A) The order of the matrix is 3 × 3

(B) |A| = 21

(C) ∣adj A∣=225|adj\ A| = 225

(D) A is skew symmetric matrix

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

For the matrix A=[2−1−10231−21]A = \begin{bmatrix} 2 & -1 & -1 \\ 0 & 2 & 3 \\ 1 & -2 & 1 \end{bmatrix}

Statement (A): The order of the matrix is 3 × 3

The matrix has 3 rows and 3 columns.

Order = 3 × 3

Statement (A) is correct.


Statement (B): |A| = 21

Expanding along the first row:

∣A∣=2∣23−21∣−(−1)∣0311∣+(−1)∣021−2∣|A| = 2 \begin{vmatrix} 2 & 3 \\ -2 & 1 \end{vmatrix} - (-1) \begin{vmatrix} 0 & 3 \\ 1 & 1 \end{vmatrix} + (-1) \begin{vmatrix} 0 & 2 \\ 1 & -2 \end{vmatrix}

=2[(2)(1)−(3)(−2)]+1[(0)(1)−(3)(1)]−1[(0)(−2)−(2)(1)]= 2[(2)(1) - (3)(-2)] + 1[(0)(1) - (3)(1)] - 1[(0)(-2) - (2)(1)]

=2[2+6]+1[0−3]−1[0−2]= 2[2 + 6] + 1[0 - 3] - 1[0 - 2]

=2(8)−3+2= 2(8) - 3 + 2

=16−3+2= 16 - 3 + 2

=15= 15

Statement (B) is incorrect.


Statement (C): ∣adj A∣=225|adj\ A| = 225

For any n×nn \times n matrix: ∣adj A∣=∣A∣n−1|adj\ A| = |A|^{n-1}

With n=3n = 3 and ∣A∣=15|A| = 15:

∣adj A∣=∣A∣3−1|adj\ A| = |A|^{3-1}

=(15)2= (15)^2

=225= 225

Statement (C) is correct.


Statement (D): A is skew symmetric matrix

A matrix is skew symmetric if AT=−AA^T = -A.

AT=[201−12−2−131]A^T = \begin{bmatrix} 2 & 0 & 1 \\ -1 & 2 & -2 \\ -1 & 3 & 1 \end{bmatrix}

−A=[−2110−2−3−12−1]-A = \begin{bmatrix} -2 & 1 & 1 \\ 0 & -2 & -3 \\ -1 & 2 & -1 \end{bmatrix}

Since AT≠−AA^T \neq -A, the matrix is not skew symmetric.

Statement (D) is incorrect.


The correct statements are (A) and (C) only.

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