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The edge of a cube is increasing at a rate of 7 cm/s. The rate of change of area of the cube when its side is 3 cm is:

Solution

✅ Correct Option: 4

The edge of a cube is increasing at a rate of 7 cm/s. The current side length is 3 cm.

Surface Area of a cube is given by:

A=6a2A = 6a^2

where aa is the side of the cube.


Differentiating both sides with respect to time:

dAdt=6×2a×dadt\dfrac{dA}{dt} = 6 \times 2a \times \dfrac{da}{dt}

dAdt=12a×dadt\dfrac{dA}{dt} = 12a \times \dfrac{da}{dt}


Given:

a=3a = 3 cm

dadt=7\dfrac{da}{dt} = 7 cm/s

Substituting these values:

dAdt=12×3×7\dfrac{dA}{dt} = 12 \times 3 \times 7

dAdt=36×7\dfrac{dA}{dt} = 36 \times 7

dAdt=252\dfrac{dA}{dt} = 252 cm²/s

Therefore, the rate of change of surface area of the cube is 252 cm²/s.

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