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If ∣x−2−33x2x∣=3\begin{vmatrix} x-2 & -3 \\ 3x & 2x \end{vmatrix} = 3, then the values of xx are:

Solution

✅ Correct Option: 4

Expanding, (x−2)(2x)−(−3)(3x)=2x2−4x+9x=2x2+5x(x-2)(2x)-(-3)(3x)=2x^2-4x+9x=2x^2+5x. Setting 2x2+5x=32x^2+5x=3 gives 2x2+5x−3=02x^2+5x-3=0, i.e. (2x−1)(x+3)=0(2x-1)(x+3)=0, so x=12x=\frac{1}{2} or x=−3x=-3.

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