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If ∫03(8x3+5x2−2x−k) dx=3\displaystyle\int_0^3 (8x^3+5x^2-2x-k)\,dx = 3, where kk is constant, then kk is equal to

Solution

✅ Correct Option: 3

Integrating gives [2x4+53x3−x2−kx]03=162+45−9−3k=198−3k\left[2x^4+\frac{5}{3}x^3-x^2-kx\right]_0^3=162+45-9-3k=198-3k. Setting 198−3k=3198-3k=3 gives 3k=1953k=195, so k=65k=65.

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