The area (in sq. units) bounded by the parabola $y^2 = x$ and line $x = 4$ in first quadrant is equal to $A$, then which of the following statements is/are TRUE ?

A. $A = \dfrac{16}{3}$

B. $A = \displaystyle\int_0^4 \sqrt{x}\, dx$

C. $A = 2\displaystyle\int_0^4 \sqrt{x}\, dx$

D. $A = \displaystyle\int_0^2 y^2\, dy$

Choose the correct answer from the options given below:

The area (in sq. units) of the region bounded by $x^2=4y, y=1, y=9$ and $x=0$ in the first quadrant is :

The area (in square units) of the region bounded by the curve $x = y^3, y = -1, y = 2$ and $x = 0$ is:

Area bounded by the curves $y = \cos^2 x, x = 0, y = 0$ and $x = \pi$, is:

The area (in sq. units) bounded by the parabola $y^2 = 4ax$, its latus rectum and the $x$-axis in the first quadrant is:

The area (in sq. units) of the region bounded by the curve $y = \sqrt{16-x^2}$ and x-axis is

The area of region bounded by the curves $4y = x^3, y = 0$ and $x = 4$ in the first quadrant is :