Skip to main contentSkip to solution

If ∣232xxx491∣+∣3245∣=0\begin{vmatrix} 2 & 3 & 2 \\ x & x & x \\ 4 & 9 & 1 \end{vmatrix} + \begin{vmatrix} 3 & 2 \\ 4 & 5 \end{vmatrix} = 0, then the value of xx is

Solution

✅ Correct Option: 2

Take xx common from the second row: the third-order determinant becomes x∣232111491∣=3xx\begin{vmatrix}2&3&2\\1&1&1\\4&9&1\end{vmatrix}=3x. The second-order determinant is 15−8=715-8=7. So 3x+7=03x+7=0 and x=−73x=-\frac73.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question