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If E and F are two independent events such that P(E)=13,P(F)=35P(E)=\dfrac{1}{3}, P(F)=\dfrac{3}{5}, then which of the following is/are correct ?

A. P(E∩F)=15P(E \cap F) = \dfrac{1}{5}

B. P(E‾F)=23P\left(\dfrac{\overline{E}}{F}\right) = \dfrac{2}{3}

C. P(EF‾)=23P\left(\dfrac{E}{\overline{F}}\right) = \dfrac{2}{3}

D. P(EF)=23P\left(\dfrac{E}{F}\right) = \dfrac{2}{3}

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Independence gives P(E∩F)=13×35=15P(E \cap F)=\frac{1}{3} \times \frac{3}{5}=\frac{1}{5}, so A is true. Conditioning on an independent event changes nothing: P(E‾∣F)=P(E‾)=23P(\overline{E} \mid F)=P(\overline{E})=\frac{2}{3}, so B is true, while P(E∣F‾)=P(E∣F)=P(E)=13P(E \mid \overline{F})=P(E \mid F)=P(E)=\frac{1}{3}, so C and D are false.

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