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The area (in sq. units) bounded by the curves x=y2x = y^2 and x=yx = y in the first quadrant is:

Solution

✅ Correct Option: 1

The curves meet where y2=yy^2=y, i.e. y=0y=0 and y=1y=1. Between these, y>y2y>y^2, so the area is ∫01(y−y2) dy=12−13=16\int_0^1(y-y^2)\,dy=\frac{1}{2}-\frac{1}{3}=\frac{1}{6}.

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