Let the random variable X follow a Poisson distribution. If P(X=3)=2/5P(X=2), then P(X=1) is equal to Option 1: 6/5e^-6/5 Option 2: 6/5e^-5/6 Option 3: 5/6e^-6/5 Option 4: 5/6e^-5/6

The answer is '6/5e^-6/5'. View full solution:

CUET Mathematics - Let the random variable X follow a Poisson distribution. If P(X=3)=2/5P(X=2), then P(X=1) is equal to | PYQs + Solutions

CUET Mathematics 2026 15th May Shift 1

Applied Mathematics

Medium

applied

$\dfrac{6}{5}e^{-\frac{6}{5}}$

$\dfrac{6}{5}e^{-\frac{5}{6}}$

$\dfrac{5}{6}e^{-\frac{6}{5}}$

$\dfrac{5}{6}e^{-\frac{5}{6}}$

✅ Correct Option: 1

Related questions:

12th May Shift 2

If a coin is tossed 8 times and getting a head is considered as success, then which of the following statements are correct ?

(A) The probability of getting 4 heads is $\dfrac{35}{128}$

(B) The mean of the number of successes is 4.

(D) The probability of getting 6 heads is $\dfrac{9}{64}$ .

Choose the correct answer from the options given below:

22nd May Shift 2

If the heights of 300 students are normally distributed with mean 68 inches and standard deviation 3 inches. If Z is the standard normal variate such that $P(0\le Z\le 1.33)=0.4082, P(Z\ge 1.33)=0.0918$ and $P(0\le Z\le 1)=0.3413$ , then which of the following statements are correct?

(A) There are 27 students whose height is greater than 72 inches.

(B) The number of students having heights less than or equal to 64 inches is 27.

(D) There are 35 students whose height is greater then 72 inches.

Choose the correct answer from the options given below:

7 June Shift 1

Match list I with list II. 4 defective pens are mixed with 10 normal pens. 3 pens are drawn one by one with replacement , then the probability distribution of the number of defective pens is :

List-I	List - II
A. P(X=0)	8/343
B. P(X=1)	60/343
C. P(X=2)	125/343
D. P(X=3)	150/343

Choose the correct option below :

CUET Mathematics 2026 15th May Shift 1 PYQs

Keyboard Shortcuts