Skip to main contentSkip to solution

If the system of equations x−ky−z=0,kx−y−z=0,x+y−z=0x - ky - z = 0, kx - y - z = 0, x + y - z = 0 has a non-zero solution, then possible values of kk are

Solution

✅ Correct Option: 1

A homogeneous system has a non-trivial solution only when the coefficient determinant vanishes. Expanding ∣1−k−1k−1−111−1∣\begin{vmatrix}1&-k&-1\\k&-1&-1\\1&1&-1\end{vmatrix} gives 2+k(1−k)−(k+1)=1−k22+k(1-k)-(k+1)=1-k^2. Setting 1−k2=01-k^2=0 gives k=1k=1 and k=−1k=-1.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question