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Maximum slope of the curve y=−x3+3x2+9x−30y = -x^3 + 3x^2 + 9x - 30 is

Solution

✅ Correct Option: 3

The slope is m=dydx=−3x2+6x+9m=\frac{dy}{dx}=-3x^2+6x+9. Maximising mm: dmdx=−6x+6=0\frac{dm}{dx}=-6x+6=0 gives x=1x=1, and d2mdx2=−6<0\frac{d^2m}{dx^2}=-6<0 confirms a maximum. Hence mmax=−3+6+9=12m_{max}=-3+6+9=12.

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