The point('s) at which the function f given by f(x) = cases |x|/2x, & x<0 \\ -1/2, & x≥0 cases is continuous is (are) Option 1: x R - \1\ : where R is set of all real numbers Option 2: x = 0 Option 3: x R: where R is set of all real numbers Option 4: x R - \0\: where R is set of all real numbers

The answer is 'x R: where R is set of all real numbers'. View full solution:

The point('s) at which the function f given by f(x) = cases |x|2x, & x =q0 cases is continuous is (are)

x R: where R is set of all real numbers

x R - \1\ : where R is set of all real numbers

x R: where R is set of all real numbers

x R - \0\: where R is set of all real numbers

CUET Mathematics - The point('s) at which the function f given by f(x) = cases |x|/2x, & x<0 \\ -1/2, & x≥0 cases is continuous is (are) | PYQs + Solutions

CUET Mathematics 2026 15th May Shift 1

Calculus

Medium

core

$x \in \mathbb{R} - \{1\}$ : where $\mathbb{R}$ is set of all real numbers

$x = 0$

$x \in \mathbb{R}$ : where $\mathbb{R}$ is set of all real numbers

$x \notin \mathbb{R} - \{0\}$ : where $\mathbb{R}$ is set of all real numbers

✅ Correct Option: 3

Related questions:

14 May Shift 1

Match List-I with List-II

$\begin{array}{|l|l|} \hline \rule{0pt}{2.8ex}\text{List-I} & \text{List-II} \\[1.2ex] \hline \rule{0pt}{2.8ex}\text{(A) } f(x) = |x| & \text{(I) Not differentiable at } x=-2 \text{ only} \\[1.2ex] \hline \rule{0pt}{2.8ex}\text{(B) } f(x) = |x+2| & \text{(II) Not differentiable at } x=0 \text{ only} \\[1.2ex] \hline \rule{0pt}{2.8ex}\text{(C) } f(x) = |x^2-4| & \text{(III) Not differentiable at } x=2 \text{ only} \\[1.2ex] \hline \rule{0pt}{2.8ex}\text{(D) } f(x) = |x-2| & \text{(IV) Not differentiable at } x=2,-2 \text{ only} \\[1.2ex] \hline \end{array}$

Choose the correct answer from the options given below:

15th May Shift 1

The graph of a function $f: R \to R$ is shown below, where $R$ is a real numbers

Then which of following statements is correct?

18th May Shift 1

Match List-I with List-II

List-I	List-II
Parametric Curve	$\dfrac{dy}{dx} =$
(A) $x = t, y = t^2$	(I) $\dfrac{3}{2}t$
(B) $x = t^2, y = t^3$	(II) $2t$
(C) $x = t^3, y = t^2$	(III) $\dfrac{1}{2t}$
(D) $x = t^2, y = t$	(IV) $\dfrac{2}{3t}$

Choose the correct answer from the options given below:

CUET Mathematics 2026 15th May Shift 1 PYQs

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