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The probability of simultaneous occurrence of at least one of two events E and F is pp. If the probability that exactly one of E, F occurs is qq, then P(E‾)+P(F‾)P(\overline{E}) + P(\overline{F}) is equal to

Solution

✅ Correct Option: 2

Let S=P(E)+P(F)S=P(E)+P(F) and I=P(E∩F)I=P(E \cap F). Then S−I=pS-I=p and S−2I=qS-2I=q, so I=p−qI=p-q and S=2p−qS=2p-q. Hence P(E‾)+P(F‾)=2−S=2−2p+qP(\overline{E})+P(\overline{F})=2-S=2-2p+q.

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