Match List-I with List-II

List-I	List-II
(A) $\begin{bmatrix} 5 & 3 \\ -7 & 1 \end{bmatrix} + \begin{bmatrix} 7 & 3 \\ 7 & 2 \end{bmatrix}$	(I) Identity matrix
(B) $\begin{bmatrix} 5 & 3 \\ -7 & 1 \end{bmatrix} + \begin{bmatrix} -4 & -3 \\ -6 & 0 \end{bmatrix}$	(II) Upper Triangular Matrix
(C) $\begin{bmatrix} 5 & -3 \\ -2 & -1 \end{bmatrix} + \begin{bmatrix} -5 & 3 \\ 2 & 1 \end{bmatrix}$	(III) Zero Matrix
(D) $\begin{bmatrix} 5 & 13 \\ -2 & 6 \end{bmatrix} + \begin{bmatrix} -4 & -13 \\ 2 & -5 \end{bmatrix}$	(IV) Lower Triangular Matrix

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If $A$ is a square matrix of order 3 and $|A|=6$, then the value of $|2A^T|$ is:

If $A = \begin{bmatrix} 3 & 7 \\ 4 & -2 \end{bmatrix}$, $X = \begin{bmatrix} \alpha \\ -2 \end{bmatrix}$, $B = \begin{bmatrix} 7 \\ 32 \end{bmatrix}$ and $AX = B$, then the value of the $\alpha$ is

Match List-I with List-II

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If $A = \begin{bmatrix} 2 & -3 & -5 \\ -1 & 4 & 5 \\ 1 & -3 & -4 \end{bmatrix}$, then $A^2$ is equal to :

If $A = \begin{bmatrix} 1 & 2 \\ 4 & -3 \end{bmatrix}$ and $f(x) = 2x^2 - 4x + 5$, the $f(A)$ is equal to

Let A and B be 3×3 matrices such that $A \neq B$. If $A^3 = B^3$ and $A^2B = B^2A$, then the determinant of $A^2 + B^2$ is: