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If '[.]' is greatest integer function, then value of ∫01.5[x2] dx\displaystyle\int_0^{1.5}[x^2]\,dx is equal to :

Solution

✅ Correct Option: 1

Here [x2]=0[x^2]=0 on [0,1)[0,1), 11 on [1,2)[1,\sqrt{2}) and 22 on [2,1.5][\sqrt{2},1.5]. So the integral is 1(2−1)+2(1.5−2)=2−1+3−22=2−21(\sqrt{2}-1)+2(1.5-\sqrt{2})=\sqrt{2}-1+3-2\sqrt{2}=2-\sqrt{2}.

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