CUET Mathematics - If C is an arbitrary constant, then Match the LIST-I with LIST-II | | LIST-I | | LIST-II | |---|---|---|---| | A. | sqrt(x^2+a^2) dx | I. | x/2sqrt(a^2-x^2) + a^2/2^-1x/a + C | | B. | sqrt(a^2-x^2) dx | II. | x + sqrt(x^2+a^2) + C | | C. | 1sqrt(x^2+a^2) dx | III. | ^-1x/a + C | | D. | 1sqrt(a^2-x^2) dx | IV. | x/2sqrt(x^2+a^2) + a^2/2 x + sqrt(x^2+a^2) + C | Choose the correct answer from the options given below: | PYQs + Solutions | AfterBoards

CUET Mathematics 2026 15th May Shift 1 PYQs

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CUET Mathematics 2026 15th May Shift 1

Calculus

>

Easy

core

A-IV, B-I, C-II, D-III

A-II, B-I, C-IV, D-III

A-IV, B-III, C-II, D-I

A-II, B-III, C-IV, D-I

✅ Correct Option: 1

Related questions:

18th May Shift 2

$\int \dfrac{e^{7\log x}-e^{6\log x}}{e^{5\log x}-e^{4\log x}}\,dx$ , $x>0$ and $x\ne 1$ is equal to (consider $\log x = \log_e x$ )

3 June Shift 1

Match List-I with List-II

List-I	List-II
Integral	Value
---	---
(A) $\int_{-1}^{1} (\vert x\vert + 1) dx$	(I) 0
(B) $\int_{-2}^{2} \vert x + 1\vert dx$	(II) 2
(C) $\int_{-1}^{1} 3\vert x^2\vert dx$	(III) 5
(D) $\int_{-1}^{1} x\vert x\vert dx$	(IV) 3

Choose the correct answer from the options given below:

22nd May Shift 1

$\int \frac{\sqrt{9+(\log x)^2}}{x} dx$ is equal to: (where $C$ is an arbitrary constant and consider $\log_e x = \log x$ )

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