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Match the LIST-I with LIST-II

LIST-ILIST-II
A. ∣x+23x+54∣=3\begin{vmatrix} x+2 & 3 \\ x+5 & 4 \end{vmatrix} = 3I. x=10x = 10
B. ∣x+2x+534∣=13\begin{vmatrix} x+2 & x+5 \\ 3 & 4 \end{vmatrix} = 13II. x=60x = 60
C. ∣x+4x−487∣=0\begin{vmatrix} x+4 & x-4 \\ 8 & 7 \end{vmatrix} = 0III. x=0x = 0
D. ∣x+48x−47∣=60\begin{vmatrix} x+4 & 8 \\ x-4 & 7 \end{vmatrix} = 60IV. x=20x = 20

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

A: 4(x+2)−3(x+5)=x−7=3⇒x=104(x+2) - 3(x+5) = x - 7 = 3 \Rightarrow x = 10

B: 4(x+2)−3(x+5)=x−7=13⇒x=204(x+2) - 3(x+5) = x - 7 = 13 \Rightarrow x = 20

C: 7(x+4)−8(x−4)=−x+60=0⇒x=607(x+4) - 8(x-4) = -x + 60 = 0 \Rightarrow x = 60

D: 7(x+4)−8(x−4)=−x+60=60⇒x=07(x+4) - 8(x-4) = -x + 60 = 60 \Rightarrow x = 0

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