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Three pipes A, B, and C can fill a tank together in 10 hours. After working at it together for 2 hours, B is closed and A and C can fill the remaining part in 12 hours. The time in which B alone can fill the tank is

Solution

✅ Correct Option: 1

The combined rate is 110\frac{1}{10} per hour, so 2 hours of joint work fills 15\frac{1}{5}. A and C fill the remaining 45\frac{4}{5} in 12 hours, a rate of 45×12=115\frac{4}{5 \times 12}=\frac{1}{15}. So B's rate is 110−115=130\frac{1}{10}-\frac{1}{15}=\frac{1}{30}, meaning B alone takes 30 hours.

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