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The maximum value of Z=3x+2yZ = 3x+2y subject to the constraints x+2y≥8x+2y \geq 8, x+y≤10,x≥0,y≥0x+y \leq 10, x \geq 0, y \geq 0 is

Solution

✅ Correct Option: 2

The feasible region has corners (0,4)(0,4), (8,0)(8,0), (10,0)(10,0) and (0,10)(0,10). Values of Z=3x+2yZ=3x+2y there are 88, 2424, 3030 and 2020. The maximum is 3030, attained at (10,0)(10,0).

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