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If f(x)=x4−2x33f(x) = x^4 - \dfrac{2x^3}{3}, then f(x)f(x) is

A. increasing in (12,∞)\left(\dfrac{1}{2}, \infty\right)

B. decreasing in (12,∞)\left(\dfrac{1}{2}, \infty\right)

C. increasing in (−∞,0)(-\infty, 0)

D. decreasing in (−∞,0)∪(0,12)(-\infty, 0) \cup \left(0, \dfrac{1}{2}\right)

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

f′(x)=4x3−2x2=2x2(2x−1)f'(x)=4x^3-2x^2=2x^2(2x-1). Since 2x2≥02x^2 \geq 0, the sign of f′f' follows 2x−12x-1: positive for x>12x>\frac{1}{2} and negative for x<12x<\frac{1}{2}, vanishing only at x=0x=0. So ff increases on (12,∞)\left(\frac{1}{2},\infty\right) and decreases on (−∞,0)∪(0,12)(-\infty,0)\cup\left(0,\frac{1}{2}\right), making A and D true.

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