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A company manufactured fans with three units A, B and C. Unit A, B and C produces 2%, 10% and 14% defective fans respectively. Units A, B and C produces 40%, 40% and 20% fans of total products respectively. A fan is randomly chosen that is found to be defective then the probability that the chosen fan is produced from unit C, is

Solution

✅ Correct Option: 1

By Bayes' theorem, P(C∣D)=0.20×0.140.40×0.02+0.40×0.10+0.20×0.14=0.0280.008+0.040+0.028=0.0280.076=719P(C \mid D)=\frac{0.20 \times 0.14}{0.40 \times 0.02 + 0.40 \times 0.10 + 0.20 \times 0.14}=\frac{0.028}{0.008+0.040+0.028}=\frac{0.028}{0.076}=\frac{7}{19}.

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