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If y=log⁡esin⁡(ex+5x+500)y = \log_e \sin(e^x + 5x + 500) then dydx\dfrac{dy}{dx} is equal to

Solution

✅ Correct Option: 1

Let u=ex+5x+500u=e^x+5x+500. By the chain rule, dydx=cos⁡usin⁡u⋅dudx=(ex+5)cot⁡(ex+5x+500)\frac{dy}{dx}=\frac{\cos u}{\sin u} \cdot \frac{du}{dx}=(e^x+5)\cot(e^x+5x+500).

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