CUET Mathematics 2026 15th May Shift 1 PYQs

$\int_{-1}^{1}\log(x+\sqrt{x^2+1})dx$ is equal to

If $\displaystyle\int\dfrac{x^3\,dx}{\sqrt{1+x^2}} = a(1+x^2)^{3/2}+b\sqrt{1+x^2}+c$, where 'C' is an arbitrary constant, then the value of $a$ and $b$ are

$\int_0^2 x(2-x)^n dx$ is equal to