Skip to main contentSkip to solution

A simple random sample of 49 items from a population with standard deviation, σ = 6 resulted in a sample mean of 32. At 95% confidence level, the margin of error is (Given Z0.025=1.96Z_{0.025} = 1.96)

Solution

✅ Correct Option: 3

Margin of error =Z0.025×σn=1.96×649=1.96×67=1.68=Z_{0.025} \times \frac{\sigma}{\sqrt{n}}=1.96 \times \frac{6}{\sqrt{49}}=1.96 \times \frac{6}{7}=1.68. The sample mean itself is not needed.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question