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If the matrix [5x23x−2x−1]\begin{bmatrix} 5 & x^2 \\ 3x-2 & x-1 \end{bmatrix} is symmetric, then values of xx are :

Solution

✅ Correct Option: 3

Symmetry requires the off-diagonal entries to be equal: x2=3x−2x^2 = 3x-2. Then x2−3x+2=0x^2-3x+2 = 0, giving x=1x = 1 and x=2x = 2.

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