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If AA and BB are two events such that P(A‾∪B‾)=23P(\overline{A} \cup \overline{B}) = \dfrac{2}{3} and P(A∪B)=59P(A \cup B) = \dfrac{5}{9}, then which of the following are TRUE?

A. P(A∩B)=13P(A \cap B) = \dfrac{1}{3}

B. P(A∪B)+P(A∩B)=79P(A \cup B) + P(A \cap B) = \dfrac{7}{9}

C. P(A)+P(B)=29P(A) + P(B) = \dfrac{2}{9}

D. P(A‾)+P(B‾)=109P(\overline{A}) + P(\overline{B}) = \dfrac{10}{9}

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 1

By De Morgan, P(A‾∪B‾)=1−P(A∩B)=23P(\overline{A}\cup\overline{B}) = 1 - P(A\cap B) = \frac{2}{3}, so P(A∩B)=13P(A\cap B) = \frac{1}{3} and A is true. Then P(A)+P(B)=59+39=89P(A)+P(B) = \frac{5}{9}+\frac{3}{9} = \frac{8}{9}, so B and C fail, and P(A‾)+P(B‾)=2−89=109P(\overline{A})+P(\overline{B}) = 2-\frac{8}{9} = \frac{10}{9} makes D true.

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