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If A=[1−23−424]A = \begin{bmatrix} 1 & -2 & 3 \\ -4 & 2 & 4 \end{bmatrix} and B=[1−23−424]B = \begin{bmatrix} 1 & -2 \\ 3 & -4 \\ 2 & 4 \end{bmatrix}, then ABAB is :

Solution

✅ Correct Option: 4

AA is 2×32\times3 and BB is 3×23\times2, so ABAB exists and is 2×22\times2. The entries are 1−6+6=11-6+6 = 1, −2+8+12=18-2+8+12 = 18, −4+6+8=10-4+6+8 = 10 and 8−8+16=168-8+16 = 16, giving [1181016]\begin{bmatrix} 1 & 18 \\ 10 & 16 \end{bmatrix}.

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