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∫x3x+2dx\displaystyle\int \dfrac{x^3}{x+2}dx is equal to: (where CC is an arbitrary constant and log⁡ex=log⁡x\log_e x = \log x)

Solution

✅ Correct Option: 1

Long division gives x3x+2=x2−2x+4−8x+2\frac{x^3}{x+2} = x^2 - 2x + 4 - \frac{8}{x+2}. Integrating term by term yields x33−x2+4x−8log⁡∣x+2∣+c\frac{x^3}{3} - x^2 + 4x - 8\log|x+2| + c.

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