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If the function f(x)=(4x−1)3sin⁡x4⋅log⁡(1+x23)f(x) = \dfrac{(4^x-1)^3}{\sin\dfrac{x}{4}\cdot\log\left(1+\dfrac{x^2}{3}\right)} is continuous at x=0x = 0, then the value of f(0)f(0) is: (Take log⁡ex=log⁡x\log_e x = \log x)

Solution

✅ Correct Option: 2

For continuity f(0)f(0) equals the limit. Using 4x−1≈xlog⁡44^x-1 \approx x\log 4, sin⁡x4≈x4\sin\frac{x}{4} \approx \frac{x}{4} and log⁡(1+x23)≈x23\log\left(1+\frac{x^2}{3}\right) \approx \frac{x^2}{3}, the expression tends to x3(log⁡4)3x3/12=12(log⁡4)3\frac{x^3(\log 4)^3}{x^3/12} = 12(\log 4)^3.

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