Area of the region bounded by the curve y = x and x-axis between x = 0 and x = is: Option 1: 2 Sq units Option 2: 3 Sq units Option 3: 4 Sq units Option 4: 1 Sq units

Answer: 2 Sq units. Solution: x is positive on (0,()/2) and negative on (()/2,), so areas must be added in magnitude: _0^(/2) x dx +, _(/2)^() x dx, = 1 + 1 = 2 square units.

Calculus

Application of Integrals

Easy

core

Area of the region bounded by the curve $y = \cos x$ and $x-axis$ between $x = 0$ and $x = \pi$ is:

2 Sq units

3 Sq units

4 Sq units

1 Sq units

✅ Correct Option: 1

$\cos x$ is positive on $(0,\frac{\pi}{2})$ and negative on $(\frac{\pi}{2},\pi)$ , so areas must be added in magnitude: $\int_0^{\pi/2}\cos x\,dx + \left|\int_{\pi/2}^{\pi}\cos x\,dx\right| = 1 + 1 = 2$ square units.

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Area of the region bounded by the curve y=cos⁡xy = \cos xy=cosx and x−axisx-axisx−axis between x=0x = 0x=0 and x=πx = \pix=π is:

Solution

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CUET Mathematics Past Year Questions (Topic-Wise)

Area of the region bounded by the curve $y = \cos x$ and $x-axis$ between $x = 0$ and $x = \pi$ is: