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If the mean and variance of a binomial distribution are 4 and 3 respectively, then the probability of getting exactly 5 successes in the distribution is:

Solution

✅ Correct Option: 3

From np=4np = 4 and npq=3npq = 3 we get q=34q = \frac{3}{4}, so p=14p = \frac{1}{4} and n=16n = 16. Hence P(X=5)=16C5(14)5(34)11P(X=5) = {}^{16}C_5\left(\frac{1}{4}\right)^5\left(\frac{3}{4}\right)^{11}.

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