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If the system of equations 2x+3y=102x + 3y = 10, x+ky=4x + ky = 4 has a unique solution, then

Solution

✅ Correct Option: 2

The system has two equations:

2x+3y=102x + 3y = 10

x+ky=4x + ky = 4


For a unique solution, the two lines must intersect at exactly one point. This occurs when the lines are not parallel.

The system has a unique solution when the ratio of coefficients of xx is not equal to the ratio of coefficients of yy:

21≠3k\frac{2}{1} \neq \frac{3}{k}


Cross-multiplying:

2k≠32k \neq 3

k≠32k \neq \frac{3}{2}


Therefore, the system has a unique solution when k≠32k \neq \frac{3}{2}.

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